If a projectile is shot at an angle of #pi/4# and at a velocity of #32 m/s#, when will it reach its maximum height??

1 Answer
Jane
Mar 2, 2018

#2.31s#

Explanation:

here,the upward movement of the projectile will be due to the upward component of its velocity i.e #32 sin (pi/4)#

So,we can apply, #v=u-g t# to find the time taken to reach its maximum height.

At,maximum height upward component of velocity is zero,initial upward velocity is #32 sin (pi/4)#

So, #t= (32 sin (pi/4))/g=2.31 s#

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