If a projectile is shot at an angle of #pi/3# and at a velocity of #1m/s#, when will it reach its maximum height??

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Answer 1 · 2016-01-09T18:36:56

After #0.088"s"#

Use the equation of motion

#v=u+at#

The vertical component of velocity is given by:

#v_y=vsintheta#

So the equation becomes:

#0=vsintheta-"g"t#

#:.t=(vsintheta)/g#

#theta=pi/3=60^@#

#:.t=1xxsin60/9.8=0.866/9.8=0.088"s"#