If a projectile is shot at an angle of #pi/12# and at a velocity of #1 m/s#, when will it reach its maximum height??

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Answer 1 · 2016-12-02T07:19:29

The maximum height is #=0.013m#

The maximum height is given by

#h_(max)=(v_0^2sin^2theta)/(2g)#

#v_0=1ms^(-1)#

#theta=pi/12#

#g=10ms^(-2)#

So,

#h_(max)=1*sin^2(pi/12)/(2*10)#

#=0.013m#