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If a projectile is shot at an angle of #(5pi)/12# and at a velocity of #16 m/s#, when will it reach its maximum height??

1 Answer

Oct 12, 2017

1.545 seconds

Explanation:

#T = (u sin θ) / g#

#T = (16 ms^-1 sin ((5 π)/12)) / (10 ms^-2)#

#T = (16 × 0.9659) / (10)# s

#T = 1.545# #text(seconds)#

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