If a projectile is shot at an angle of $(5pi)/12$ and at a velocity of $15 m/s$ , when will it reach its maximum height??

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If a projectile is shot at an angle of $(5pi)/12$ and at a velocity of $15 m/s$ , when will it reach its maximum height??

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Answer 1 · 2017-03-22T22:25:50

10.711 meters

Explanation:

Split the velocity up into x-components and y-components:

$vx=15cos(5pi/12)$

$vy=15sin(5pi/12)$

We only care about the y-component in this case since we want to know maximum height. The initial velocity is $15sin(5pi/12)$ . The final velocity will be $0$ at the top. The acceleration is always $9.8$ m/s downwards. We need to find d. Find a kinematics equation that has $vi$ , $vf$ , $a$ , and $d$ .

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The equation in the top right corner has all four of those components. Plug into that equation:

$0=(15sin(5pi/12))^2+2(-9.8)(d)$

Solve for d:

$d=(-15sin(5pi/12))^2/((2)(-9.8))=10.711 m$

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If a projectile is shot at an angle of $(5pi)/12$ and at a velocity of $15 m/s$ , when will it reach its maximum height??

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

If a projectile is shot at an angle of (5pi)/12(5pi)/12 and at a velocity of 15 m/s15 m/s, when will it reach its maximum height??

1 Answer

Explanation:

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Impact of this question

If a projectile is shot at an angle of $(5pi)/12$ and at a velocity of $15 m/s$ , when will it reach its maximum height??