If a projectile is shot at an angle of #(3pi)/8# and at a velocity of #12 m/s#, when will it reach its maximum height?

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Answer 1 · 2017-07-23T15:12:25

#t=1.1secs#

Maximum height is reached when the vertical component of velocity #=0#

the initial vertical component #" u=12sin((3pi)/8)#

we will use

#v=u + g t uarr#

#=12sin((3pi)/8)-10t#

#t=12/10sin((3pi)/8)#

#t=1.1secs#