If a projectile is shot at an angle of (2pi)/32π3 and at a velocity of 26 m/s26ms, when will it reach its maximum height?

1 Answer
Apr 4, 2016

t_m=2,29 " s"tm=2,29 s

Explanation:

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"given data:"given data:
"initial velocity :"v_i=26 m/sinitial velocity :vi=26ms
"angle :"alpha=(2pi)/3angle :α=2π3
sin(2pi)/3=0,866sin(2π)3=0,866
"elapsed time to reach its maximum height :"t_m=(v_i*sin alpha)/gelapsed time to reach its maximum height :tm=visinαg
g=9,81 m/s^2g=9,81ms2

t_m=(26*0,866)/(9,81)tm=260,8669,81

t_m=2,29 " s"tm=2,29 s