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If a projectile is shot at an angle of #(2pi)/3# and at a velocity of #23 m/s#, when will it reach its maximum height?

1 Answer

May 2, 2016

#t=2,03 " s"#

Explanation:

#" you can use the formula "t=(v_i*sin alpha)/g#

#v_i=23 m/s#

#alpha=(2pi)/3#

#g=9,81#

#t=(23*sin((2pi)/3))/(9,81)#

#t=2,03 " s"#

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