# If a distribution has a mean of 266 and standard deviation of 16, what is the z-score of 282?

May 26, 2018

$4$

#### Explanation:

Assuming a Normal distribution

X~N(266,16)

$z = \frac{x - \mu}{\sigma}$

$z = \frac{282 - 266}{\sqrt{16}}$

$z = \frac{16}{4} = 4$