If a ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second, for how long will the ball be going upward?

Question

4258 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-03-24T14:32:31

The answer is: #1,73s#.

First of all: #v=56(feet)/s~=17m/s#.

This is an uniformed accelerated motion with

#a=-g=-9.8m/s^2#, and the law is:

#v=v_0+atrArrv=v_0-g trArrt=(v_0-v)g#.

Since #v_0=17m/s# and #v=0m/s# (in the higher point his speed is 0),

#t=(17m/s)/(9.8m/s^2)=1,73s#.