If $a=12, b=9$ , and $c=4$ , what is $(b^2-2c^2)/(a+c-b)$ ?

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Answer 1 · 2018-03-30T12:29:43

See a solution process below:

Substitute:

and then calculate the result:

$(color(blue)(b)^2 - 2color(green)(c)^2)/(color(red)(a) + color(green)(c) - color(blue)(b))$ becomes:

$(color(blue)(9)^2 - (2 * color(green)(4)^2))/(color(red)(12) + color(green)(4) - color(blue)(9)) =>$

$(81 - (2 * 16))/(16 - color(blue)(9)) =>$

$(81 - 32)/7 =>$

$49/7 =>$

$7$

If a=12, b=9a=12, b=9, and c=4c=4, what is (b^2-2c^2)/(a+c-b)(b^2-2c^2)/(a+c-b)?