If a #11 kg# object moving at #45 m/s# slows down to a halt after moving #900 m#, what is the coefficient of kinetic friction of the surface that the object was moving over?

1 Answer
P dilip_k
Apr 23, 2016

By conservation of mechanical energy
Work done against Frictional force = KE of the object
#mu_kxxmxxgxxd=1/2xxmv^2#
#mu_k=v^2/(2gd)=45^2/(2xx10xx900)=0.1125#

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