If 8 moles of magnesium chloride react with enough aluminum, how many moles of aluminum chloride are produced? 3 MgCl2 + 2 Al → 3 Mg + 2 AlCl3

1 Answer
BRIAN M.
May 5, 2014

You begin with the balanced chemical equation

#3MgCl_2 + 2Al -> 3Mg + 2AlCl_3#

The mole ratios for this equation are

3 moles #MgCl_2# : 2 moles Al : 3 moles Mg : 2 moles #AlCl_3#

Therefore if 8.0 moles of #MgCl_2# react we can use the mole ration between #MgCl_2# and #AlCl_3# to determine the amount of ammonium chloride can theoretically be produced.

8.0 mol #MgCl_2# x #(2 mol AlCl_3) / (3mol MgCl_2)# = 5.3 mol #AlCl_3#

I hope this was helpful.
SMARTERTEACHER

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