If 60 liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, what will the new volume of the gas be?

1 Answer
Jan 21, 2016

Data:-
Initial Volume#=V_1=60 liter#
Initial Temperature#=T_1=546K#
Final Temperature#=T_2=273K#
Final Vloume#=V_2=??#
Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,
#V_1/T_1=V_2/T_2#

#implies V_2=(V_1*T_2)/T_1=(60*273)/546=60/2=30liter#

#implies V_2=30 liter#

Hence the new volume of the gas is #30 liter#