If #4^x= 7#, then what does #4^ (-2x)# equal? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer iceman · Becca M. · Don't Memorise Sep 1, 2015 If #4^x = 7# then #4^(-2x) = 1/49# Explanation: #4^x = 7# #4^(-2x)# #= 1/4^(2x)# #= 1/[(4^x)^2]# #= 1/(7)^2# #= 1/49# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 35746 views around the world You can reuse this answer Creative Commons License