If #2x^2 – 3xy + y^2 + x + 2y – 7 = 0#, then #dy/dx# is equal to –?
Ans: #(3y-4x-1)/(2y-3x+2)#
Ans:
1 Answer
Jan 2, 2018
the answer as given is :
Explanation:
derive the equation first:
rewrite it:
rewrite:
divide by dx:
divide by 2y-3x+2
and you have the final answer