If 200 mL of a 2.50 M NaOH solution is diluted to 500 mL, what is the new concentration of NaOH?

1 Answer
anor277
Nov 2, 2016

The new concentration is 1.00*mol*L^-1.

Explanation:

"Concentration" = "Moles of solute"/"Volume of solution"

We use this relationship to get the initial number of moles, by taking the product,"concentration"xx"volume", and then dividing this molar quantity by the new volume, which we get by simply adding the 2 given volumes.

And thus, (200xx10^-3cancelLxx2.50*mol*L^-1)/(500xx10^-3cancelL)

And we get an answer with units mol*L^-1 as we require.

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