If 15 moles of water was made in this reaction, how many grams of carbon dioxide were made? #H_2CO_3rarrH_2O+CO_2#

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Answer 1 · 2018-02-12T14:22:39

#660.15"g"# of carbon dioxide was produced.

We have the equation #H_2CO_3rarrH_2O+CO_2#.

The moles of water and carbon dioxide are in the ratio #1:1#.

So #15# moles of water and #15# moles of carbon dioxide are produced.

The formula for moles is #n=m/M#, where #m# is the mass of the substance and #M# its molar mass.

Rearranging the equation we get #m=nM#.

We have #15"mol"# of carbon dioxide and the molar mass of the gas is #44.01"g"/"mol"#.

Inputting:

#m=15*44.01#

#m=660.15"g"# of carbon dioxide was produced.