If 113.0 g of iron reacts with 138.0 g of chlorine gas, what is the limiting reactant?

1 Answer
anor277
Jul 11, 2017

Both #"ferrous chloride"#, #FeCl_2#, and #"ferric chloride"#, #FeCl_3#, can be made by direct combination of the elements.......

Explanation:

Let's assume that it is #FeCl_2#, i.e.

#Fe(s) + Cl_2(g) rarrFeCl_2(s)#

#"Moles of iron"=(113.0*g)/(55.8*g*mol^-1)=2.04*mol#......

#"Moles of"# #Cl_2# #"gas"# #=(138.0*g)/(70.9*g*mol^-1)=1.95*mol#......

And since there is a slightly less molar quantity of #Cl_2# with respect to the metal, then chlorine gas is the reagent in deficiency, i.e. the limiting reactant.

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