If 10 raise to power 21 molecules are removed from 200 mg of CO2,then how many moles of CO2 are left?(Old and urgently dear experts)

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If 10 raise to power 21 molecules are removed from 200 mg of CO2,then how many moles of CO2 are left?(Old and urgently dear experts)

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Answer 1 · 2016-09-26T14:10:31

$Molar mass of C O_{2} =44g/ m o l$ $"Molar mass of "CO_2"=44g/"mol"$

$Amount of C O_{2} taken = 200 m g = \frac{0.2 g}{44 \frac{g}{mol}}$ $"Amount of "CO_2 " taken"=200mg=(0.2g)/(44g/"mol")$
$= 4.55 \times 10^{- 3} m o l$ $=4.55xx10^-3mol$

$Number of mlecules of C O_{2} removed = 10^{21}$ $"Number of mlecules of "CO_2" removed"=10^21$

$1 mol = 6.023 \times 10^{23} molecules of C O_{2}$ $"1 mol = "6.023xx10^23 "molecules of "CO_2$

$10^{21} molecules = \frac{10^{21}}{6.023 \times 10^{23}} m o l$ $10^21" molecules "=10^21/(6.023xx10^23)mol$

$= 1.66 \times 10^{- 3} m o l$ $=1.66xx10^-3mol$

$C O_{2} left = (4.55 - 1.66) \times 10^{- 3} m o l$ $CO_2" left"=(4.55-1.66)xx10^-3mol$
$= 2.89 \times 10^{- 3} m o l$ $=2.89xx10^-3mol$

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If 10 raise to power 21 molecules are removed from 200 mg of CO2,then how many moles of CO2 are left?(Old and urgently dear experts)

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