If 10 raise to power 21 molecules are removed from 200 mg of CO2,then how many moles of CO2 are left?(Old and urgently dear experts) Chemistry Stoichiometry Mole Ratios 1 Answer P dilip_k Sep 26, 2016 "Molar mass of "CO_2"=44g/"mol" "Amount of "CO_2 " taken"=200mg=(0.2g)/(44g/"mol") =4.55xx10^-3mol "Number of mlecules of "CO_2" removed"=10^21 "1 mol = "6.023xx10^23 "molecules of "CO_2 10^21" molecules "=10^21/(6.023xx10^23)mol =1.66xx10^-3mol CO_2" left"=(4.55-1.66)xx10^-3mol =2.89xx10^-3mol Answer link Related questions Question #a106e Question #e2e86 Question #a1072 Question #c5bf1 Question #dc373 Question #c5bf9 Question #a1076 Question #dc377 Question #b984f Question #19ea3 See all questions in Mole Ratios Impact of this question 63535 views around the world You can reuse this answer Creative Commons License