How would you simplify #sqrt6 * sqrt2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Sheffy Apr 27, 2016 #2sqrt3# Explanation: We can write the numbers as #sqrt(2xx3)xxsqrt2# #=sqrt2 xx sqrt3 xx sqrt2# Here, #color(red)( sqrt2xxsqrt2=sqrt(2xx2)=2)# #=2xxsqrt3# #=2sqrt3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3746 views around the world You can reuse this answer Creative Commons License