How would you simplify $sqrt48/sqrt3$ ?

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Answer 1 · 2018-04-14T13:38:48

$4$

$"using the "color(blue)"law of radicals"$

$•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)$

$rArrsqrt48/sqrt3=sqrt(48/3)=sqrt16=4$

How would you simplify sqrt48/sqrt3sqrt48/sqrt3?