How would you simplify #6 times sqrt2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Meave60 Feb 12, 2017 #6sqrt2# Explanation: #6xxsqrt2=6sqrt2# It's just like multiplying #6xx x#. The answer is #6x#, and we understand that this means #6xx x#. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3205 views around the world You can reuse this answer Creative Commons License