How would you simplify #3 sqrt16#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Mar 3, 2016 #=color(blue)(12# Explanation: #3sqrt16# #sqrt16=sqrt (2*2*2*2) = sqrt(2^2 *2^2) = sqrt(4*4) =sqrt(4^2) = color(blue)(4# So, #3sqrt16= 3 xx color(blue)(4# #=color(blue)(12# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 930 views around the world You can reuse this answer Creative Commons License