How would you simplify $(2 \sqrt{7} - 4 \sqrt{3}) (4 \sqrt{7} + 8 \sqrt{3})$ $(2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)$ ?

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How would you simplify $(2 \sqrt{7} - 4 \sqrt{3}) (4 \sqrt{7} + 8 \sqrt{3})$ $(2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)$ ?

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Answer 1 · 2016-02-18T21:38:01

-40

Explanation:

$(2 \sqrt{7} - 4 \sqrt{3}) (4 \sqrt{7} + 8 \sqrt{3})$ $(2sqrt(7)-4sqrt(3))(4sqrt(7)+8sqrt(3))$

You have to use the distributive operation of multiplication:

$2 \sqrt{7} \times 4 \sqrt{7} + 2 \sqrt{7} \times 8 \sqrt{3} - 4 \sqrt{3} \times 4 \sqrt{7} - 4 \sqrt{3} \times 8 \sqrt{3}$ $2sqrt(7)xx4sqrt(7)+2sqrt(7)xx8sqrt(3)-4sqrt(3)xx4sqrt(7)-4sqrt(3)xx8sqrt(3)$

= $2 \times 4 \times 7 + 2 \times 8 \times \sqrt{7} \times \sqrt{3} - 4 \times 4 \times \sqrt{3} \times \sqrt{7} - 4 \times 8 \times 3$ $2xx4xx7+2xx8xxsqrt(7)xxsqrt(3)-4xx4xxsqrt(3)xxsqrt(7)-4xx8xx3$

= $56 + 16 \sqrt{21} - 16 \sqrt{21} - 96 = - 40$ $56+16sqrt(21)-16sqrt(21)-96=-40$

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How would you simplify $(2 \sqrt{7} - 4 \sqrt{3}) (4 \sqrt{7} + 8 \sqrt{3})$ $(2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)$ ?

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How would you simplify (2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)(2√7−4√3)(4√7+8√3)(2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)?

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How would you simplify $(2 \sqrt{7} - 4 \sqrt{3}) (4 \sqrt{7} + 8 \sqrt{3})$ $(2 sqrt 7 - 4 sqrt3)(4 sqrt 7 + 8 sqrt3)$ ?