How would you simplify #2 sqrt 3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer LM Dec 24, 2016 #sqrt(12)# Explanation: though it may not be a simplification, #2sqrt(3)# can be shown as #sqrt(12)#. #2 = sqrt(4)# #sqrt(3)=sqrt(3)# #sqrt(4)*sqrt(3) = sqrt(4*3)# #=sqrt(12)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 40662 views around the world You can reuse this answer Creative Commons License