How would you find the exact value of the six trigonometric function of 45 degrees?

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How would you find the exact value of the six trigonometric function of 45 degrees?

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Answer 1 · 2016-06-18T07:24:02

See explanation.

Explanation:

An angle of $45^o$ can be found in a unit square divided by its diagonal. The catheti of this right triangle are $1$ unit long, the hypotenuse is $sqrt(2)/2$ units long, so:

$sin 45^o=cos45^o=a/c=sqrt(2)/2$

$tan45^o=cot45^o=a/a=1$

$sec45^o=csc45^o=c/a=sqrt(2)$

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How would you find the exact value of the six trigonometric function of 45 degrees?

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Explanation:

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