How would you find the exact value of the six trigonometric function of -3pi/2?

1 Answer
Leland Adriano Alejandro
Jun 26, 2016

sin ((-3pi)/2)=1," " "cos ((-3pi)/2)=0," " "tan ((-3pi)/2)=oo

csc ((-3pi)/2)=1," " "sec ((-3pi)/2)=oo," " "cot ((-3pi)/2)=0

Explanation:

sin ((-3pi)/2)=sin ((pi)/2)=1,
cos ((-3pi)/2)=cos ((pi)/2)=0,
tan ((-3pi)/2)=tan ((pi)/2)=oo

csc ((-3pi)/2)=csc ((pi)/2)=1,
sec ((-3pi)/2)=sec ((pi)/2)=oo,
cot ((-3pi)/2)=cot ((pi)/2)=0

God bless....I hope the explanation is useful.

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