How would you find the exact value of the six trigonometric function of 19pi/3?

1 Answer
Nghi N
Nov 29, 2016

Find trig function values

Explanation:

Use trig unit circle and trig table of special arcs -->
sin ((19pi)/3) = sin (pi/3 + 6pi) = sin (pi/3) = sqrt3/2
cos ((19pi)/3) = cos (pi/3) = 1/2
tan ((19pi)/3) = sin/(cos) = sqrt3
cot ((19pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3
sec ((19pi)/3) = 1/(cos) = 2
csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3

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