How would you determine the oxidation number for sodium sulfate?

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How would you determine the oxidation number for sodium sulfate?

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Answer 1 · 2015-11-06T21:13:14

Oxygen assumes its usual oxidation state of $- I I$ $-II$ . Therefore, $S$ $S$ here has its maximum oxidation number of $V I^{+}$ $VI^+$ .

Explanation:

Sum up the oxidation numbers: $4 \times (- I I) + S_{O N} = 2^{-}$ $4xx(-II) + S_(ON) = 2^-$ , the charge on anion. Therefore, $S_{O N} = ? ?$ $S_(ON) = ??$ How would you determine the oxidation numbers of the sulfurs in thiosulfate anion, $S_{2} O_{3}^{2 -}$ $S_2O_3^(2-)$ ?

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How would you determine the oxidation number for sodium sulfate?

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