How would you calculate the molar solubility of Mn(OH)2 (Ksp = 1.6e-13) in pure water? Chemistry Solutions Factors Affecting Solubility 1 Answer anor277 · Stefan V. Nov 11, 2015 #Mn(OH)_2(s) rightleftharpoons Mn^(2+) + 2OH^-# #K_(sp) = 1.6xx10^(-13)# Explanation: #K_(sp) = 1.6xx10^(-13)=[Mn^(2+)][OH^-]^2# If we call the solubility of manganese(II) hydroxide #S#, then by the stoichiometry of the reaction: #K_(sp)=S(2S)^2=4S^3#. So #S = root(3)((1.6 xx 10^(-13))/4)# Answer link Related questions What factors affect solubility in a solid-liquid combination? What factors affect solubility in water? What factors affect solubility of ionic compounds? What factors affect the solubility of gases in liquids? What factors affect the solubility of a solid? How can I calculate solubility of potassium nitrate? What does the solubility of KNO3 depend on? How can I calculate the solubility of solute in a solution? How is solubility affected by polymer chain structure? Does solubility differ from molar solubility? See all questions in Factors Affecting Solubility Impact of this question 25743 views around the world You can reuse this answer Creative Commons License