how would I find range of this e.g (6/(2x+3)) for x>0 I will put zero in place of x and find range that is 2 but I don't know it will be greater or less than x?

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Answer 1 · 2018-04-05T09:02:40

The range is $y in RR-{0}$

To find the range, proceed as follows

Let $y=6/(2x+3)$

$y(2x+3)=6$

$2xy+3y=6$

$2xy=6-3y$

$x=(6-3y)/(2y)$

The denominator is $!=0$

Therefore,

$y!=0$

The range is $y in RR-{0}$

graph{6/(2x+3) [-18.02, 18.01, -9.01, 9.01]}