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How would I determine the value of the trig ratios when I'm given the angle in radians for example #cot 0.942#?

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May 13, 2015

Since #pi# equals 3.14, 0.942 would be #pi/10#. Therefore, if #cot (pi/10)# is given, all trignometrical ratios can be determined.

#Sin (pi/10) = 1/sqrt(1+cot^2 (pi/10)#
#cos (pi/10)= sqrt (1- sin^2 (pi/10)#

#tan(pi/10)= 1/cot(pi/10)#

#csc(pi/10)= sqrt(1+cot^2 (pi/10)#

#sec(pi/10)= 1/cos (pi/10)#

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