How to the missing value?

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Answer 1 · 2017-10-14T20:42:15

#log(2)/log(1.087)~~8.309# years

Initial Investment = #19000/2=9500#

let #y# be the number of years it will take to double

#9500 * 1.087^y=19000#

#=>1.087^y=2#

logarithmic rules state #log(a^x)=x*log(a)#

#=>log(1.087^y)=log(19000)#

#=>y*log(1.087)=log(19000)#

#=>x=log(2)/log(1.087)~~8.309# years