How to solve this picture algebra question?

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Answer 1 · 2018-01-12T06:14:51

Third-Place Seller Profit $= $ 36$ $=$36$

Second-Place Seller Profit $= $ 72$ $=$72$

First-Place Seller Profit $= $ 92$ $=$92$

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Let's let the amount that goes to the third-place seller be $x$ $x$ . Then, we can list the amounts that each get as follows:

Third Place Seller $= x$ $=x$

Second-Place Seller $= 2 x$ $=2x$

First-Place Seller $= 2 x + 20$ $=2x+20$

Now, we can add them up and set the result equal to the total amount of profit available for them to share:

$x + 2 x + 2 x + 20 = 200$ $x+2x+2x+20=200$

$5 x + 20 = 200$ $5x+20=200$

$5 x = 200 - 20$ $5x=200-20$

$5 x = 180$ $5x=180$

$x = \frac{180}{5} = 36$ $x=180/5=36$

Third-Place Seller Profit $= $ 36$ $=$36$

Second-Place Seller Profit $= 2 ($ 36) = $ 72$ $=2($36)=$72$

First-Place Seller Profit $= $ 72 + $ 20 = $ 92$ $=$72+$20=$92$

They add up to $$ 36 + $ 72 + $ 92 = $ 200$ $$36+$72+$92=$200$

I can not draw the picture the problem asked but I am sure you can take care of that.