How to solve the mentioned problem?

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How to solve the mentioned problem?

$\frac{d}{d x} (ln (x - \sqrt{x^{2} - 1})) = ?$ $d/(dx)(ln(x-sqrt(x^2-1)))=?$

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Answer 1 · 2017-12-21T15:59:00

$\frac{d}{d x} ln (x - \sqrt{x^{2} - 1}) = - \frac{1}{\sqrt{x^{2} - 1}}$ $d/dx ln(x-sqrt(x^2-1)) =-1/sqrt(x^2-1)$

Explanation:

Using the chain rule:

$\frac{d}{d x} ln (x - \sqrt{x^{2} - 1}) = \frac{1}{x - \sqrt{x^{2} - 1}} \frac{d}{d x} (x - \sqrt{x^{2} - 1})$ $d/dx ln(x-sqrt(x^2-1)) = 1/(x-sqrt(x^2-1)) d/dx (x-sqrt(x^2-1))$

$\frac{d}{d x} ln (x - \sqrt{x^{2} - 1}) = \frac{1}{x - \sqrt{x^{2} - 1}} (1 - \frac{x}{\sqrt{x^{2} - 1}})$ $d/dx ln(x-sqrt(x^2-1)) = 1/(x-sqrt(x^2-1)) (1-x/sqrt(x^2-1))$

$\frac{d}{d x} ln (x - \sqrt{x^{2} - 1}) = \frac{1}{x - \sqrt{x^{2} - 1}} \frac{\sqrt{x^{2} - 1} - x}{\sqrt{x^{2} - 1}}$ $d/dx ln(x-sqrt(x^2-1)) = 1/(x-sqrt(x^2-1)) (sqrt(x^2-1)-x)/sqrt(x^2-1)$

$\frac{d}{d x} ln (x - \sqrt{x^{2} - 1}) = - \frac{1}{\sqrt{x^{2} - 1}}$ $d/dx ln(x-sqrt(x^2-1)) =-1/sqrt(x^2-1)$

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Math

Humanities

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How to solve the mentioned problem?

$\frac{d}{d x} (ln (x - \sqrt{x^{2} - 1})) = ?$ $d/(dx)(ln(x-sqrt(x^2-1)))=?$

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How to solve the mentioned problem?

ddx(ln(x−√x2−1))=?d/(dx)(ln(x-sqrt(x^2-1)))=?

1 Answer

Explanation:

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Impact of this question

$\frac{d}{d x} (ln (x - \sqrt{x^{2} - 1})) = ?$ $d/(dx)(ln(x-sqrt(x^2-1)))=?$