How to solve $tan x < | 1 |$ $tan x < |1|$ ?

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Answer 1 · 2017-12-31T13:23:41

See below.

Since this is an absolute value, our range is $tan x < 1$ $tanx <1$ and $tan x > - 1$ $tanx> -1$ . This puts $x$ $x$ in:

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And gives the ranges:

$\frac{7 π}{4} < x < \frac{π}{4}$ $(7pi)/4 < x < pi/4$

$\frac{3 π}{4} < x < \frac{5 π}{4}$ $(3pi)/4 < x < (5pi)/4$

How to solve tanx<|1|tan x < |1|?