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How to solve #tan x < |1|#?

1 Answer

Dec 31, 2017

See below.

Explanation:

Since this is an absolute value, our range is #tanx <1# and #tanx> -1#. This puts #x# in:

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And gives the ranges:

#(7pi)/4 < x < pi/4#

#(3pi)/4 < x < (5pi)/4#

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