How to solve : (px^2-4+5x)/(p^3x-x^2) = 1 ?

1 Answer
Sunayan S
Apr 6, 2018

(px^2-4+5x)/(p^3x-x^2)=1

=>px^2-4+5x=p^3x-x^2

=>px^2-4+5x-p^3x+x^2=0

=>(p+1)cdot x^2-(p^3-5)cdot x-4=0

  • Applying Shreedhar Acharya's Formula,

x=((p^3-5)+-sqrt((p^3-5)^2+4xx4xx(p+1)))/(2 cdot (p+1)

x=((p^3-5)+-sqrt(p^6-10p^3+25+16p+16))/(2 cdot (p+1)

x=((p^3-5)+-sqrt(p^6-10p^3+16p+41))/(2 cdot (p+1)

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