How to solve : # (px^2-4+5x)/(p^3x-x^2) = 1# ?
1 Answer
Apr 6, 2018
#(px^2-4+5x)/(p^3x-x^2)=1#
#=>px^2-4+5x=p^3x-x^2#
#=>px^2-4+5x-p^3x+x^2=0#
#=>(p+1)cdot x^2-(p^3-5)cdot x-4=0#
- Applying Shreedhar Acharya's Formula,
#x=((p^3-5)+-sqrt((p^3-5)^2+4xx4xx(p+1)))/(2 cdot (p+1)#
#x=((p^3-5)+-sqrt(p^6-10p^3+25+16p+16))/(2 cdot (p+1)#
#x=((p^3-5)+-sqrt(p^6-10p^3+16p+41))/(2 cdot (p+1)#
