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How to simplify #sin^2x/(cos^2+3cosx+2)=(1-cosx)/(2+cosx)#?

#(Sin^2X)/(cos^2x+3cosX+2)=(1-cosX)/(2+cosx)#

1 Answer

Feb 1, 2018

#LHS=sin^2x/(cos^2x+3cosx+2)#

#=sin^2x/(cos^2x+cosx+2cosx+2)#

#=(1-cos^2x)/((cosx(cosx+1)+2(cosx+1))#

#=((1-cosx)(1+cosx))/((cosx+1)(cosx+2))#

#=(1-cosx)/(2+cosx)=RHS#

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