How to find the vector unit normal?

Question

#bbr(t)=sqrt(2)tbbi+e^tbbj-e^-tbbk#
#t=0#

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Answer 1 · 2018-03-31T23:48:29

#bbr(0)=bbj-bbk#

We have #bbr(t)=sqrt2tbbi+e^tbbj-e^(-t)bbk#. To find #bbr(0)#, we simply plug #0# into the equation.

#bbr(0)=sqrt2(0)bbi+e^0bbj-e^-0bbk=bbj-bbk#