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How to find the antiderivative of #(5x)/(x^2-1)dx#?

1 Answer

Mar 1, 2015

The answer is: #y'=ln|x^2-1|+c#.

Since

#int(f'(x))/f(x)dx=ln|f(x)|+c#,

than:

#int(5x)/(x^2-1)dx=5/2int(2x)/(x^2-1)dx=ln|x^2-1|+c#.

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