# How to find domain for f(x)=sqrt(x+4)?

##### 2 Answers
Sep 25, 2015

Domain $x \ge - 4$

#### Explanation:

The domain is the set of $x$ values that your function can accept. In this case you have a square root that cannot accept a negative argument.
So you may say that must be:
$x + 4 \ge 0$
or
$x \ge - 4$ meaning that as long as $x$ is equal or bigger than $- 4$ it is ok!

Refer to explanation

#### Explanation:

When you have a function with formula

$f \left(x\right) = \sqrt{g \left(x\right)}$ where g(x) is a polynomial then for the function f
to be defined we need the condition that $g \left(x\right) \ge 0$.

Hence in our case $g \left(x\right) = x + 4$ hence $x + 4 \ge 0$ or $x \ge - 4$

So the domain is $D \left(f\right) = \left[- 4 , + \infty\right)$