How to find critical points and the using the first derivative test for f(x) = 3x^4 - 4x^3 + 6? Calculus Graphing with the First Derivative Identifying Stationary Points (Critical Points) for a Function 1 Answer Nghi N. ยท Kevin B. Apr 16, 2015 f(x) = 3x^4 - 4x^3 + 6 Derivative: f'(x) = 12x^3 - 12x^2 = 12x^2*(x - 1) f'(x) = 0 when x = 0 and x = 1. The critical points are: (0, 6) and (1, 5). Answer link Related questions How do you find the stationary points of a curve? How do you find the stationary points of a function? How many stationary points can a cubic function have? How do you find the stationary points of the function y=x^2+6x+1? How do you find the stationary points of the function y=cos(x)? How do I find all the critical points of f(x)=(x-1)^2? Let h(x) = e^(-x) + kx, where k is any constant. For what value(s) of k does h have... How do you find the critical points for f(x)=8x^3+2x^2-5x+3? How do you find values of k for which there are no critical points if h(x)=e^(-x)+kx where k... How do you determine critical points for any polynomial? See all questions in Identifying Stationary Points (Critical Points) for a Function Impact of this question 2310 views around the world You can reuse this answer Creative Commons License