How to do question 8?

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How to do question 8?

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Answer 1 · 2018-02-12T10:21:00

$a = \frac{3}{16}$ $a=3/16$ , $h = - 2$ $h=-2$ , $k = 3$ $k=3$

Explanation:

It appears that by turning point it means that $(- 2, 3)$ $(-2,3)$ is the vertex and hence asthe equation $y = a {(x - h)}^{4} + k$ $y=a(x-h)^4+k$ is in vertex form, where $(h, k)$ $(h,k)$ is vertex, we have the equation as

$y = a {(x - (- 2))}^{4} + 3$ $y=a(x-(-2))^4+3$ or $y = a {(x + 2)}^{4} + 3$ $y=a(x+2)^4+3$

Now, it passes through point $(0, - 6)$ $(0,-6)$ hence

$6 = a {(0 + 2)}^{4} + 3$ $6=a(0+2)^4+3$ or $6 = 16 a + 3$ $6=16a+3$ i.e. $a = \frac{3}{16}$ $a=3/16$

Hence, equation is $y = \frac{3}{16} {(x + 2)}^{4} + 3$ $y=3/16(x+2)^4+3$

i.e. $a = \frac{3}{16}$ $a=3/16$ , $h = - 2$ $h=-2$ , $k = 3$ $k=3$ and graph appears as

graph{3/16(x+2)^4+3 [-12.67, 7.33, -0.96, 9.04]}

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How to do question 8?

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