How to determine a temperature on which process is spontaneous by using function of Gibbs free energy?

Seems like this question can't be solved, maybe I just need any correlation between temperature and gibbs free energy?

1 Answer
jos
Jul 11, 2018

If #Delta S>0#
#(Delta H) / (Delta S) < T#
If #Delta S<0#
#(Delta H) / (Delta S) > T#

Explanation:

#Delta G = Delta H - T Delta S#
G is gibbs free energy
H is enthalpy
S is entropy
#Delta G = - T Delta S_"net"#
If #Delta S_"net" < 0#
#DeltaG = - T Delta S_"net"<0(because T>0K)#, the process is spontaneous.

If #Delta H# and #Delta S# is given,
#Delta H - T Delta S<0#
#Delta H < T Delta S#
If #Delta S>0#
#(Delta H) / (Delta S) < T#
If #Delta S<0#
#(Delta H) / (Delta S) > T#

Related questions
See all questions in Gibbs Free Energy
Impact of this question
1862 views around the world
You can reuse this answer
Creative Commons License