How this reaction (during qualitative analysis) is possible: $Zn^(2+)$ + NaOH ------> $Zn(OH)2$ + $Na^(2+)$ if Zinc is below Sodium in the reactivity series?

Question

How this reaction (during qualitative analysis) is possible: $Zn^(2+)$ + NaOH ------> $Zn(OH)2$ + $Na^(2+)$ if Zinc is below Sodium in the reactivity series?

In qualitative analysis zinc's reaction with Sodium hydroxide produces $Zn(OH)2$ which is soluble in excess of NaOH. I mean how is this possible: Zn displacing more reactive metal Na.

1 Answer

Impact of this question

5207 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-24T08:00:18

?

Explanation:

you are confused. Na is the more reactive, while Na+ (and not Na2+, that doesn't exist) is a spectator ion. Zn2+ is an amphoteric ion. The doer with zinc is the hydroxyl ion

Science

Math

Humanities

... and beyond

How this reaction (during qualitative analysis) is possible: $Zn^(2+)$ + NaOH ------> $Zn(OH)2$ + $Na^(2+)$ if Zinc is below Sodium in the reactivity series?

In qualitative analysis zinc's reaction with Sodium hydroxide produces $Zn(OH)2$ which is soluble in excess of NaOH. I mean how is this possible: Zn displacing more reactive metal Na.

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How this reaction (during qualitative analysis) is possible: Zn^(2+)Zn^(2+) + NaOH ------> Zn(OH)2Zn(OH)2 + Na^(2+)Na^(2+) if Zinc is below Sodium in the reactivity series?

In qualitative analysis zinc's reaction with Sodium hydroxide produces Zn(OH)2Zn(OH)2 which is soluble in excess of NaOH. I mean how is this possible: Zn displacing more reactive metal Na.

1 Answer

Explanation:

Related questions

Impact of this question

How this reaction (during qualitative analysis) is possible: $Zn^(2+)$ + NaOH ------> $Zn(OH)2$ + $Na^(2+)$ if Zinc is below Sodium in the reactivity series?

In qualitative analysis zinc's reaction with Sodium hydroxide produces $Zn(OH)2$ which is soluble in excess of NaOH. I mean how is this possible: Zn displacing more reactive metal Na.