How much lead can be extracted from 254.3 g of lead (IV) oxide?

1 Answer
anor277
Oct 29, 2016

Approx. 215*g.

Explanation:

"Moles of plumbic oxide" = (254.3*g)/(239.3*g*mol^-1), which is slightly over a mole.

And thus an equivalent quantity of lead metal can be extracted,

i.e.: (254.3*g)/(239.3*g*mol^-1)xx207.2*g*mol^-1 = ??g

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