How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?

Question

4041 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-16T03:07:08

It will require the removal of $"75200 J"$ of energy.

Use the heat of fusion equation:

$q=m*H_"f"$ ,

where:

$q$ is the amount of energy, $m$ is mass in grams, and $H_"f"$ is the heat of fusion.

Known

$"mass", m="225 g"$

$"heat of fusion of water", H_"f"="334 J/g"$

Unknown

$"energy removed", q"$

Solution

Plug in the known values and solve.

$q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J"$ rounded to three significant figures