How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?

1 Answer
Jul 16, 2018

It will require the removal of "75200 J" of energy.

Explanation:

Use the heat of fusion equation:

q=m*H_"f",

where:

q is the amount of energy, m is mass in grams, and H_"f" is the heat of fusion.

Known

"mass", m="225 g"

"heat of fusion of water", H_"f"="334 J/g"

Unknown

"energy removed", q"

Solution

Plug in the known values and solve.

q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J" rounded to three significant figures