How much heat is required to completely melt a 19.5 gram sample of ice at 0 degrees Celsius?

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Answer 1 · 2018-02-13T13:59:02

$65325J$ or $65.3kJ$

Well, we would have to use the formula:

$q=mL_f$

since we want to calculate the energy used to melt the substance

$m$ is the mass of the substance in $kg$

$L_f$ is the latent heat of fusion of the substance (since ice turns to water)

Here, $m=0.195kg$ , $L_f=3.35*10^5 J"/"kg$

$:.q=0.195cancel(kg)*3.35*10^5J"/"cancel(kg)=65325J~~65.3kJ$

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