How many valence electrons does $F$ $F$ have?

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How many valence electrons does $F$ $F$ have?

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Answer 1 · 2018-05-21T00:25:15

$7$ $7$

Explanation:

Fluorine's electron configuration is:

$[H e] 2 s^{2} 2 p^{5}$ $[He]2s^2\2p^5$ or $1 s^{2} 2 s^{2} 2 p^{5}$ $1s^2\2s^2\2p^5$

Therefore, its valence shell is $n = 2$ $n=2$ , and so it contains $2 + 5 = 7$ $2+5=7$ valence electrons. Since it is one electron away from achieving an electron configuration of neon, a noble gas, would you expect fluorine to have high electronegativity or not?

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How many valence electrons does $F$ $F$ have?

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